What will be the pressure of the gaseous mixture when 0.5 L of at 0. 8 bar and 2.0 L of dioxygen at 0.7 bar are introduced in a 1 L vessel at 27°C ?
Answers
Answered by
2
P1V1 = P2V2
0.8 × 0.5 L = 1L × P2
P2 = 0.4 bar
P1 V1= P2 V2
0.7 bar 2.0 = P2 × 1
P2 = 1.4 bar
Total pressure = 0.4 bar + 1.4 bar = 1.8 bar.
Answered by
1
Answer:
(i) The partial pressure of hydrogen gas
P
′
=
V
′
PV
=
1
0.8×0.5
=0.40 bar
(ii) The partial pressure of oxygen gas
P
′′
=
V
′
PV
=
1
0.7×2.0
=1.40 bar
So, the total pressure of gaseous mixture is P+P
′′
=0.40+1.40=1.80 bar
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