Question

what will be the probablity of getting a number 3 in a throw a dice

Answer 1

Total outcomes = 6
Favourable outcomes = 1
P (getting a 3) = 1/6

Answer 2

Hi there!
Here's the answer:

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Let S be Sample space
S = {1, 2, 3, 4, 5, 6}

n(S) - No. of total outcomes when a dice is rolled
n(S) = 6^(1) = 6

°•° Total no. of outcomes when 'n' dice are rolled = 6^n


Let E be the event of getting 3 when a dice is rolled.
E= {3}

n(E) - no. of favourable cases for Event E to occur.
n(E) =1

Probability of an Event
= (Favourable outcomes) / (Total possible outcomes)

Probability = n(E) / n(S)

•°• Required Probability = 1/6


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:)
Hope it helps