What will be the product if bacl2 is react with Naso4 (barium chloride) + (sodium sulphate) =====> ?
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That position means that it is an enormous atom, and that it will form an enormous cation Ba(2+), and this is the species that will exist in aqueous solution when you dissolve salts of the type BaCl2: BaCl2(s) → Ba(2+)(aq) + 2 Cl(-)(aq)
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Explanation:
Barium Chloride + sodium sulphate → Barium sulphate + Sodium Chloride
BaCl2 + Na2(SO4) → BaSO4 + 2NaCl
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