what will be the radius and CSA of a cone made from quadrant of circle of radius 2.8
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area of the quadrant if the given circle will be 1/4 × π × r^2= 1/4×22/7 ×2.8×2.8= CSA of the cone made =πr'L = 22/7×r '×L=6.16 m^2
so r'=6.16/π×L
as L here will be 2.8
so r'=0.70
where r' is the area of the base of the cone
L is slant height of the cone that is 2.8 here
Thanks
so r'=6.16/π×L
as L here will be 2.8
so r'=0.70
where r' is the area of the base of the cone
L is slant height of the cone that is 2.8 here
Thanks
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