Question

what will be the radius of the turn where a vehicle can pass with a safe speed of 10m/s on a banked road of angle 45 degree
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Answer 1

Answer:

the radius of the turn is 10.20 m

Explanation:

velocity= 10m/s, θ=45°

tan45°=1 here g=9.8m/s²

v=√(r g tanθ)

10=√(r × 9.8×1)

squaring on both sides

100=r× 9.8

r=100/9.8 = 10.20 m