Question

what will be the ratio of areas of the two parallelograms which lie on the same base and between the same parallels ? explain the solution

Answer 1

answer=1 this might help you

Answer 2

Answer:

Ratio of areas = 1:1

Step-by-step explanation:

Ratio of Parallelograms on the same base and between the same parallels are 1:1

Given:

Two parallelogram ABCD and ABEF on the same base AB and between the same parallels AB and FC.

To Prove:

$\frac{area\:of \:ABCD}{area\:of\:ABEF}=1$

Proof:

1. In ∆BCE and ∆ADF , we have :

i) BC = AD

/* Opposite sides of a parallelogram are equal */

ii) <BCE =<ADF

/* Corresponding angles are equal, as BE parallel to AF and FC is the transversal */

iii) <BEC = <AFD

2. ∆BCE congruent to ∆ADF

/* AAS - axiom of congruence */

3. area of ∆BCE = area of ∆ADF

/* Congruent figures are equal in area */

4. area (ABED)+area (∆BCE) = area (ABED) + area ∆ADF

/* Adding same area on both sides of 3 */

5. Area of ABCD = Area of ABEF

6. Ratio of areas = 1:1

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