What will be the reminder on dividing a term of the sequence 3n+7 by its common difference
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Answered by
7
1st term = 3×1+7 = 10
2nd term = 3×2+7 = 13
Common difference = 3
If we divide the terms of this sequence by common difference we get remainder as 1.
Answered by
2
Step-by-step explanation:
- 1 term 3×1+7 = 10
- 2 term 3×2+7 = 13
- common difference =3
- I hope that this will help
- have a great day
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