Math, asked by makaylabrown6083, 1 year ago

What will be the reminder when 3^287 is divided by 23

Answers

Answered by Shardul27
1
It's so big.

So,
 {3}^{287} \div 23 = 3.73312273E+135.





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Answered by eesh2004
10

Answer:

3

Step-by-step explanation:

If you use Modular arithmetic, 3^22 is congruent to 1 (mod 23).

Now, 287=(3^22)^13 X 3

thus, 3^287 will be congruent to 1^13 X 3 (mod 23)

which leaves you with 3 (mod 23)

thus , 3 is the remainder.

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