What will be the resistance o the wire when it isbfolded to half?
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It becomes one fourth of the original.
R1 = ρ ℓ1 / A1
R2 = ρ ℓ2 / A2 = ρ ½ ℓ1 / (2 A1) = ¼ ρ ℓ1 / A1 = ¼ R1
R1 = ρ ℓ1 / A1
R2 = ρ ℓ2 / A2 = ρ ½ ℓ1 / (2 A1) = ¼ ρ ℓ1 / A1 = ¼ R1
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It becomes one fourth of the original resistance
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