What will be the resistivity of a metal wire of 3 m length and 0.4 mm in diameter, if the resistance of the wire is 55 Ω.
Answers
Answer:
Ømegam . Explanation: Given that, . length of wire l = 2 m. Resistance R = 30 ohm. diameter d = ...
The resistivity of the metal is \rho = 4.239\times10^{-6}\ \text{\O}mega mρ=4.239×10
−6
Ømegam .
Explanation:
Given that,
length of wire l = 2 m
Resistance R = 30 ohm
diameter d =0.6 mm
Radius = 0.3 mm
We know that,
The resistivity of the metal is
R = \dfrac{\rho l}{A}R=
A
ρl
\rho = \dfrac{RA}{l}ρ=
l
RA
....(I)
Put the value of R,l and A in equation (I)
\rho = \dfrac{30\times3.14\times3\times3\times10^{-8}}{2}ρ=
2
30×3.14×3×3×10
−8
\rho= 423.9\times10^{-8}\ \text{\O}mega mρ=423.9×10
−8
Ømegam
\rho = 4.239\times10^{-6}\ \text{\O}mega mρ=4.239×10
−6
Ømegam
Hence, The resistivity of the metal is \rho = 4.239\times10^{-6}\ \text{\O}mega mρ=4.239×10
−6
Ømegam
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