Question

what will be the result in F2 generation when homozygous white male rabbit is crosses with a homozygous black female Rabbit ?​

Answer 1

Explanation:

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According to the law of dominance, a trait is represented by two contrasting factors of a gene in a heterozygous individual while the homozygous individual carries two copies of same factors. Thus, the genotype of heterozygous rabbit will be Bb and that of homozygous recessive will be bb. Law of segregation states that the two factors for a trait, present together in a heterozygous individual (Bb), do not get mixed and are separated and delivered singly during gametogenesis. Thus, the heterozygous individual produces two types of gametes: 50% gametes with “B” and 50% with “b”. The homozygous recessive individual will make all gametes with “b” allele only. Fertilization of gamete with “b” allele from a recessive parent with that carrying “b” allele from the heterozygous parent will produce homozygous recessive progeny (bb); not “Bb”. Thus, the correct answer is option C.

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Answer 2

Answer:

According to the law of dominance, a trait is represented by two contrasting factors of a gene in a heterozygous individual while the homozygous individual carries two copies of same factors. Thus, the genotype of heterozygous rabbit will be Bb and that of homozygous recessive will be bb. Law of segregation states that the two factors for a trait, present together in a heterozygous individual (Bb), do not get mixed and are separated and delivered singly during gametogenesis. Thus, the heterozygous individual produces two types of gametes: 50% gametes with “B” and 50% with “b”. The homozygous recessive individual will make all gametes with “b” allele only. Fertilization of gamete with “b” allele from a recessive parent with that carrying “b” allele from the heterozygous parent will produce homozygous recessive progeny (bb); not “Bb

Explanation: