Question

yor
3abx +
262 = 0
Az 902 6h24
14
64​

Answer 1

Answer:

a²x²-3abx+2b²

= a²x²-2abx+b²+b²-abx

= (ax-b)²-b(ax-b)

= (ax-b)(ax-b) - b(ax-b)

= (ax-b)(ax-b-b)

= (ax-b)(ax-2b)