Question

what will be the shortest distance from the parbola,y^2=4ax.... from point (0,3)​

Answer 1

Answer:

The point on the parabola y2=4axnearest to the focus has its abscissa.

A .

x=0

B .

x=a

C .

x=2a

D .

x=2a

ANSWER

Let P(x,y) be the required point on the parabola which is nearest to the focus.

Then D=(x−a)2+y2

Now y2=4ax

So, D=(x−a)2+4ax

D=(x+a)2

D=(x+a)

Now, the distance will be shortest when x=0.

Hope this helps you.

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