What will be the shortest wavelength of absorption lines in H-atom corresponding to lyman series?
(A)517A
(B)911A
(C)628A
(D)1342A
Answers
Answer:
911A is the shortest wavelength of absorption lines in H-atom corresponding to the Lyman series
Explanation:
- The hydrogen atom is the only atomic system observed in nature, hence it produces the only of that collection. When the beam of mild or any radiation is made to go into the device through a slit, every individual aspect of the mild or radiation shapes images of the source. The shortest wavelength will own the least spaced spectral traces and it is known as the collection limit.
LYMAN SERIES:
- The series was discovered during the years 1906-1914, via way of means of Theodore Lyman. Thus it is known after him. According to Bohr’s model, Lyman collection is displayed whilst electron transition takes area from better energy states(nh=2,3,4,5,6,…) to nl=1 energy state. All the wavelength of the Lyman collection falls in the Ultraviolet band.
From the line spectrum of hydrogen, we know that
For the Lyman series,
n1=1
For the shortest 'wavelength' of the Lyman series, the energy difference in two levels showing transition should be maximum (i.e.,
n2=∞
we know that, = 1098678
1 / λ = (1/1 - 1/∞)
λ = 1/109678 ⇒ 911.7×
λ = 911.7A
#SPJ2
Answer:
The shortest wavelength λ is 911.7 ×
Explanation:
Rydberg's formula
- The mathematical formula used to determine the wavelength of light is known as the Rydberg formula.
- The energy of an electron changes when it transitions from one atomic orbit to another.
- The photon of light is produced when the electron transitions from a high-energy orbit to a lower-energy state.
Rydberg's formula is
1 /λ =
For hydrogen,
Z=1 and for Lyman series,
=1 and = ∞
(for shortest wavelength)
on substituting values we get
1 /λ = 109678 × ×
= 109678 c/m
λ = 9.117 ×
λ = 911.7 ×
Final answer:
The shortest wavelength λ is 911.7 ×
#SPJ2