what will be the smallest number divisible by 6,8,18,24 and 36?
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Question :- what will be the smallest number divisible by 6,8,18,24 and 36 ?
Solution :-
To find the smallest number divisible by given numbers , we will find LCM of all the given numbers.
Prime factors of 6,8,18,24 and 36 :-
→ 6 = 2 * 3
→ 8 = 2 * 2 * 2
→ 18 = 2 * 3 * 3 = 2 * 3²
→ 24 = 2 * 2 * 2 * 3 = 2³ * 3
→ 36 = 2 * 2 * 3 * 3
LCM = 2³ * 3² = 8 * 9 = 72.
Hence, the smallest number divisible by 6,8,18,24 and 36 is 72.
Learn more :-
Q3. All numbers divisible by both 20 and 23
are also divisible by which of the following? (
20 ਅਤੇ 23ਦੋਵਾਂ ਦੁਆਰਾ ਵੰਡੀਆਂ ...
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