Question

What will be the solution of question 12 and 13?

Answer 1

Hey! Here's your answer!

Question 12 :-

Angle BAN = CAN = [180 - (65 + 33)]/2 ------------> Angle Bisector

Angle BAN = CAN = 41°

in triangle ANC,

Angle CAN = 41°

Angle C = 33°

So Angle ANM =  41 + 33 = 74° -----------> Exterior angle theorem

Angle AMN = 90°

By Angle sum property,

Angle MAN = 16°

Question 13 :-

Angle C > Angle B

Angle BAD = Angle CAD = A/2

By exterior Angle Theorem in triangle ADC,

Angle ADB = A/2 + C -----------> (1)

By exterior Angle Theorem in triangle ABD,

Angle ADC = A/2 + B ---------------> (2)

But we know that Angle B < Angle C

So by equations 1 and 2,

Angle ADB > Angle ADC.

Hope this helps! :)

Answer 2

Ans 12= Angle MAN = 16 degrees