Question

what will be the tempreture of water if we mix a 50 degree of 1 liter water to another 30 degree of water

Answer 1

around 40 degree Celsius
between 50 and 30 degree Celsius

Answer 2

Given :

V₁ = 1 l

V₂ = 1 l

Specific heat capacity is the same for both .

By principle of mixtures :-

V₁ c ( t₁ - t ) = V₂ c ( t - t₂ )

Cancel V₁ and V₂ both sides [ they are equal ]

Also cancel c both sides :

==> t₁ - t =  t - t₂

==> 50 - t = t - 30

==> - t - t = - 30 - 50

==> - 2 t = -80

==> t = -80 / - 2

==> t = 40

The resultant temperature would be 40°C

Hope it helps :-)

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