What will be the time period of a simple pendulum if the pendulum is taken to a place where the value of g is 1/9 times that on the surface of two earth ?
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Answer:
T = 2(pi) sqrt [L/g]
explanation:
So, if you make the length 1/9 of the original, the new length becomes, L/9. Put it into the equation, you will get the new time period as 1/3 of the original time period.
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