Question

What will be the unit digit of the squares of the following numbers?
(i) 81 (ii) 272 (iii) 799 (iv) 3853
(v) 1234 (vi) 26387 (vii) 52698 (viii) 99880
(ix) 12796 (x) 55555

Answer 1

Answer:

(i) 9

by making 9x9=81

(ii) 17x16

Answer 2

Answer:

1,4,1,9,6,9,4,0,6,5

Step-by-step explanation:

First I will solve (iii) 799 so you can understand well.

Take unit digit 9. square it :  $9^{2}$ = 81 . Unit digit of 81 is 1.

so Ans= 1

Similarly,

(i) 81 ⇒ $1^{2} =1$ ⇒ Ans= 1

ii) 272 ⇒ $2^{2} =4$ ⇒ Ans= 4  

(iii) 799 ⇒ $9^{2} =81$ ⇒ Ans= 1

(iv) 3853 ⇒ $3^{2} =9$ ⇒ Ans= 9

(v) 1234 ⇒ $4^{2} =16$ ⇒ Ans= 6

(vi) 26387 ⇒ $7^{2} =49$ ⇒ Ans= 9

(vii) 52698 ⇒ $8^{2} =64$ ⇒ Ans= 4

(viii) 99880 ⇒ $0^{2} =0$ ⇒ Ans= 1

(ix) 12796 ⇒ $6^{2} =36$ ⇒ Ans= 6

(x) 55555 ⇒ $5^{2} =25$ ⇒ Ans= 5

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