What will be the value of a if 3a2+x+a equals 8 when x=1
Answers
Answered by
0
3a2+1+a=8
6a+1+a=8
7a=8-1
7a=7
a=7÷7
a=1
1829:
Its 3a square
Answered by
0
by putting value of x=1 we get
3a^2 + 1 + a = 8
3a^2 + a --7 =0
mark answer as brainlist
3a^2 + 1 + a = 8
3a^2 + a --7 =0
mark answer as brainlist
Attachments:
Similar questions