Question

what will be the value of acceleration due to gravity at a height 2R from the surface of earth in m/s

where g=GM/r2


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Answer 1

Answer:

Value of acceleration due to gravity at height comparable with radius of earth is given by

g' = g(R/(R+h))^2

In problem h = 2R

g' = g(R/3R)^2 = g/9

Or( 1/9)th of acceleration due to gravity on surface of earth.

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