Question

What will be the value of (alpha/beta + beta/alpha) if alpha and beta are the zeroes of the polynomial 6x² + x -2?​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

-25/12

Step-by-step explanation:

(α/β)+(β/α)

p(x)=6x^2+x-2

∴ α+β= -b/a= -1/6

αβ=c/a = -2/6 = -1/3

(α/β)+(β/α)

Taking LCM

(α^2+β^2)/αβ

We know, a^2+b^2= (a+b)^2-2ab

∴(α^2+β^2)/αβ=((α+β)^2 - 2αβ)/αβ

Substituting the values, we get,

((-1/6)^2 -2(-1/3))/(-1/3)

(1/36+2/3)/(-1/3)

((1+24)/36)/(-1/3)

-(25/36)*3

-25/12

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