Question

what will be the value of g on the surface of
earth if its mass was twice and its radius
half of wat it is now?​

Answer 1

Explanation:

GM/r^2 ×8=8g. crushed on this new gravity.

Answer 2

As we Know the formula :

g= GM/R²----------------(1)

where g is acceleration due to gravity

M is mass of the earth

R is radius of earth

G is universal gravitational constant.

If mass is twice =2M

RADIUS is half= R/2

let g1 be the new gravity .

Substituting in formula (1) we get.

g1= Gx2M/(R/2)²

g1=8 (GM/R²)

g1= 8xg

So the new gravity would be 8 times of original value that is 9.8 m/s².

Hence g1=78.4m/s²