Question

What will be the value of k If the lines given by 3x + 2ky = 12 and 2x + 4y = 8

are parallel.​

Answer 1

$\large\mathrm\blue{✎~k=3~✍}$

Answer:

Given- they are parallel

means $\frac{a1}{a2}=~\frac{b1}{b2}=\frac{c1}{c2}$

$\frac{a1}{a2}=~\frac{3x}{2x}$

$\frac{b1}{b2}=~\frac{2ky}{4y}$

$\frac{c1}{c2}=~\frac{12}{8}$

*

Solve

$\frac{a1}{a2}~=~\frac{b1}{b2}=\frac{c1}{c2}$

-->$\frac{3}{2}=\frac{2ky}{4y}=\frac{3}{2}$

we know that 2ky/4y = 3/2

value of k =

2ky/4y = 3/2

2k/4 = 3/2

2k= 6

k= 3

Value of k= 3

*by putting the k value

2ky/4y=6y/4y= 3/2