Question

What will be the value of K so that the quadratic equation Kx2-2Kx+6=0 has two equal roots ?

Answer 1

Answer:

Value of k = 0 Or k=6

Step-by-step explanation:

Given Quadratic equation:

kx²-2kx+6=0 has equal roots.

Compare above equation with

ax²+bx+c=0 we get

a = k , b = -2k , c = 6

Now ,

Discreminant (D)=0

given roots are equal ; therefore

b²-4ac=0

=> (-2k)²-4×(k)×6 = 0

=> 4k²-24k=0

=> 4k(k-6)=0

=> 4k=0 Or k-6=0

=> k=0 Or k=6

Therefore,.

Value of k = 0 Or k=6

i hope it will help u

Answer 2

Answer:

Applying Discriminant=b^2- 4ac

4k^2 - 24k=0

Solving we get k=0,6 as the equation is quadratic k=6 is the correct answer( k cannot be equal to zero because for k=0 it will give 0=6 which is incorrect)