Question

What will be the value of quotient if (8x + 2y +2z)^3 is divided by (4x + y + z)^3?

Answer 1

To find ,






Quotient when ,






${(8x + 2y + 2z)}^{3} \div {(4x + y + z)}^{3}$





Main solution :-






$\frac{ {(8x + 2y + 2z)}^{3} }{ {(4x + y + z)}^{3} }$





Well know ,






$\frac{ {a}^{m} }{ {b}^{m} } = { (\frac{a}{b}) }^{m}$





Therefore,






${ (\frac{8x + 2y + 2z}{4x + y + z}) }^{3}$






Taking 2 as common in numerator.






${( \frac{2(4x + y + z)}{4x + y + z}) }^{3}$






Now 4x + y + z will get cancelled out.






${ (\frac{2 \times 1}{1}) }^{3}$





${2}^{3}$





$8$





The quotient is 8. ( Answer )

Answer 2

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vijiharsha434

29.09.2018

Math

Secondary School

+13 pts

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What will be the value of quotient if (8x + 2y +2z)^3 is divided by (4x + y + z)^3?

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Prakhar2908

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To find ,

Quotient when ,

{(8x + 2y + 2z)}^{3} \div {(4x + y + z)}^{3}

Main solution :-

\frac{ {(8x + 2y + 2z)}^{3} }{ {(4x + y + z)}^{3} }

Well know ,

\frac{ {a}^{m} }{ {b}^{m} } = { (\frac{a}{b}) }^{m}

Therefore,

{ (\frac{8x + 2y + 2z}{4x + y + z}) }^{3}

Taking 2 as common in numerator.

{( \frac{2(4x + y + z)}{4x + y + z}) }^{3}

Now 4x + y + z will get cancelled out.

{ (\frac{2 \times 1}{1}) }^{3}

{2}^{3}

8

The quotient is 8. ( Answer )

Step-by-step explanation: