Question

What will be the value of s after this command: A = [1:4; -2:2:5; 3 1 0 -1]; s = A(end-1,end-1);

Answer 1

Given :

A = [1 : 4 ; -2 : 2 : 5 ; 3 1 0 -1];

s = A(end - 1 , end - 1);

Solution :

A = [1 : 4 ; -2 : 2 : 5; 3 1 0 -1];

This will give us matrix

1 : 4 = 1 2 3 4

-2 : 2 : 5 = -2 0 2 4

3 1 0 -1 = 3 1 0 -1

So, matrix will be :

1       2       3       4

-2     0       2       4

3       1       0      -1

Number of rows (R)= 3

Numbers of columns (C)= 4

s = A(end-1 , end-1);

A(end - 1 , end -1) = A(R - 1 , C - 1) = A(3 - 1 , 4 - 1) = A(2 , 3)

We got the coordinates : (2 , 3)

So, s will store the element which is at the position (2 , 3)

So, s = 2

Finally the value of s is 2.