what will be the value of the given no. How to find it with simple method.
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Hey it is very simple....
Let us assume that..
x=414x=414
⇒x4=4⇒x4=4
⇒x4–(2–√)4=0⇒x4–(2)4=0
⇒[x2+(2–√)2][x2−(2–√)2]=0⇒[x2+(2)2][x2−(2)2]=0
⇒x2−(2–√)2=0⇒x2−(2)2=0
⇒[x+2–√][x−2–√]=0⇒[x+2][x−2]=0
⇒x−2–√=0⇒x=2–√⇒x−2=0⇒x=2
Or x=−2–√x=−2
And x2+(2–√)2=0x2+(2)2=0
⇒x=±i2–√⇒x=±i2
Hence the required fourth roots of 44 are ±2–√,±i2–√±2,±i2
Problem is done.
Hope it helps u
Thanks
Happy diwali ☺ ☺ ☺ ❤
Please mark as brainliest answer
Any doubt then comment
Let us assume that..
x=414x=414
⇒x4=4⇒x4=4
⇒x4–(2–√)4=0⇒x4–(2)4=0
⇒[x2+(2–√)2][x2−(2–√)2]=0⇒[x2+(2)2][x2−(2)2]=0
⇒x2−(2–√)2=0⇒x2−(2)2=0
⇒[x+2–√][x−2–√]=0⇒[x+2][x−2]=0
⇒x−2–√=0⇒x=2–√⇒x−2=0⇒x=2
Or x=−2–√x=−2
And x2+(2–√)2=0x2+(2)2=0
⇒x=±i2–√⇒x=±i2
Hence the required fourth roots of 44 are ±2–√,±i2–√±2,±i2
Problem is done.
Hope it helps u
Thanks
Happy diwali ☺ ☺ ☺ ❤
Please mark as brainliest answer
Any doubt then comment
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