What will be the value of the kinetic energy(ek) of a moving body with mass m,if its speed is doubled from v to 2v?
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kinetic energy is directly proportional to v^2
coz mass is constant
so new kinetic energy changes as (2v)^2 =4v^2
so kinetic energy increases 4 times
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0
See know that kinetic energy KE=mv²/2
Now, if mass is m and v is doubled to 2v, from the equation, we get
KÉ=m(2v)²/2
=m4v²/2
Dividing this equation by the first one, we get
4. This implies that the ratio is 4:1. Hence, the kinetic energy has been increased by 4 times its original value.
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