Chemistry, asked by pratibhanaruka, 8 months ago

what will be the vapour pressure of a solution at 100°C containing 3g cane sugar in 70g water?

Answers

Answered by ronaldoChristiano

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Answered by laxmitomar1983

Answer:

756.90mm

Explanation:

weight of solute(sugar) = 3g

weight of solvent (water) = 70 g. sugar:C6H12O11

moles of solute = w/h.w = 3/342

moles of solvent = w/h.w = 70/18

according to routs law,

P°-P/P°= no. of solute /no. of solvent =

=760-P/760=3/342/70/18

P =756.90mm

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