what will be the vapour pressure of a solution at 100°C containing 3g cane sugar in 70g water?
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Answer:
756.90mm
Explanation:
weight of solute(sugar) = 3g
weight of solvent (water) = 70 g. sugar:C6H12O11
moles of solute = w/h.w = 3/342
moles of solvent = w/h.w = 70/18
according to routs law,
P°-P/P°= no. of solute /no. of solvent =
=760-P/760=3/342/70/18
P =756.90mm
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