what will be the volume occupied by 10 g of oxygen at 25 degree celcius and 600 ml volume at 27 degree celcius
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According to ideal gas equation PV=nRT
P=pressure of gas,V=volume of gas=volume of container,
T=temperaturue
V1 =INITIAL VOLUME ,V2 =FINAL VOLUME
T1 =INITIAL TEMPERATURE =27+273=300
T2 =FINAL TEMPERATURE
According to question,
V2 =2 x V1
Therefore,
V1/V2 = T1/T2
V1/2V1=300/T2
T2 =FINAL TEMPERATURE=600K
P=pressure of gas,V=volume of gas=volume of container,
T=temperaturue
V1 =INITIAL VOLUME ,V2 =FINAL VOLUME
T1 =INITIAL TEMPERATURE =27+273=300
T2 =FINAL TEMPERATURE
According to question,
V2 =2 x V1
Therefore,
V1/V2 = T1/T2
V1/2V1=300/T2
T2 =FINAL TEMPERATURE=600K
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