What will be the weight of CaO obtained by heating 300 kg of 90 % pure CaCO3
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CaCO3 --> CaO + CO2
Pure CaCO3 = (90/100) × 300
= 270g
GMM of CaCO3 = 80g
,, ,, CaO = 36g
80g CaCO3 forms 36g CaO
270g ,, ,,. (36/80) × 270 = 121.5g CaO
(Please let me know if this answer is correct or wrong)
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