Question

what will be the word reaction of lead nitrate and potassium iodide solutions

Answer 1

lead nitrate+ pottasium iodide = lead iodide, + pottasium nitrate

Answer 2

I) Pb(NO3)2+2KI→PbI2+2KNO3

Explanation:

We must first convert from a word equation to a symbol equation:

Lead (II) Nitrate + Potassium Iodide → Lead (II) Iodide + Potassium Nitrate

The lead (II) ion is represented as Pb2+, whilst the nitrate ion is NO−3. To balance the charges, we require two nitrate ions per lead (II) ion, and so lead (II) nitrate is Pb(NO3)2 .

The potassium ion is K+ and the iodide ion is I−. The two charges balance in a 1:1 ratio, so potassium iodide is simply KI.

In lead (II) iodide, the charges balance in a 1:2 ratio, so the formula is PbI2.

Finally, in potassium nitrate, the charges balance in another 1:1 ratio, giving a formula of KNO3 .

The symbol equation is as follows:

Pb(NO3)2+KI→PbI2+KNO3

The most obvious change we must make, when balancing this equation, is to increase the number of nitrate ions on the right hand side of the equation. We can do this by placing a coefficient of 2 before the potassium nitrate:

Pb(NO3)2+KI→PbI2+2KNO3

In doing this we have upset the balance of potassium ions on each side of the equation. Again, we can fix this: we must simply place another coefficient of 2, this time before the potassium iodide:

Pb(NO3)2+2KI→PbI2+2KNO3

Checking over the equations once more, you will notice that we initially had 1 iodide ion on the right hand side, but 2 on the left. However, we already dealt with this in balancing our potassium ions. Now, our equation is balanced.

And that's it! One last thing to add is that you may have noticed the irregularity in iodide ions rather than nitrate ions. In this case, you would have arrived at the same answer simply by working backwards.


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