Question

What will be the work done when 5 coloumb of charged particles are moved between two points maintained at a potential difference of 6 volt ?​

Answer 1

as we know,

$potential \: difference = \frac{work \: done}{charge}$

given:-

$potential \: difference = 6 \: v$

$charge = 5 \: c$

put the value in formula:-

$6 = \frac{work \: done}{5}$

$work \: done \: = 5 \times 6 \: joule$

$work \: done \: = 30 \: joule$