What will be the zeroes of 4u²+8u?
please send complete solving asap
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Answer:
4u²+8u
Let 4u common
4u(u+2)
Zeroes of 4u and u+2
4u=0
u=0
AND
u+2=0
u=-2.
Hence the zeroes of 4u²+8u = 0 & -2.
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