Math, asked by ShrutiMehra, 9 months ago

What will be the zeroes of 4u²+8u?
please send complete solving asap​

Answers

Answered by MohdShaharyar
2

Answer:

4u²+8u

Let 4u common

4u(u+2)

Zeroes of 4u and u+2

4u=0

u=0

AND

u+2=0

u=-2.

Hence the zeroes of 4u²+8u = 0 & -2.

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