Chemistry, asked by Jaissica12, 1 year ago

what will be volume of ammonia formed if 2L of nitrogen is mixed with 2L of hydrogen at constant temperature and pressure?

Answers

Answered by geopraneet
69

Answer:

1.33

Explanation:

For a normal reaction

N2+3H2---->2NH3

we are given

2L of N2 and 2L of H2

So now multiply the equation by 2

2N2+6H2--->4NH3

Here H2 is the limiting factor

2*3H2--->4NH3

2H2---->(4/3)NH3

4/3=1.33

THERRFORE 1.33L OF NH4 IS PRODUCED

Answered by RomeliaThurston
41

Answer: The volume of ammonia formed will be 1.33 L

Explanation:

The chemical equation for the formation of ammonia is:

N_2+3H_2\rightarrow 2NH_3

According to the mole concept:

1 mole of a compound contains 22.4 L of volume.

By Stoichiometry of the reaction:

67.2 L of hydrogen reacts with 22.4 L of nitrogen

So, 2 L of hydrogen will react with = \frac{22.4L}{67.2L}\times 2L=0.66L of hydrogen.

As, the given amount if more than the required amount. Thus, hydrogen is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

67.2 L of hydrogen produces 44.8 L of ammonia.

Thus, 2 L of hydrogen will produce = \frac{44.8L}{67.2L}\times 2L=1.33L of ammonia.

Thus, the volume of ammonia formed will be 1.33 L

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