what will be volume of ammonia formed if 2L of nitrogen is mixed with 2L of hydrogen at constant temperature and pressure?
Answers
Answer:
1.33
Explanation:
For a normal reaction
N2+3H2---->2NH3
we are given
2L of N2 and 2L of H2
So now multiply the equation by 2
2N2+6H2--->4NH3
Here H2 is the limiting factor
2*3H2--->4NH3
2H2---->(4/3)NH3
4/3=1.33
THERRFORE 1.33L OF NH4 IS PRODUCED
Answer: The volume of ammonia formed will be 1.33 L
Explanation:
The chemical equation for the formation of ammonia is:
According to the mole concept:
1 mole of a compound contains 22.4 L of volume.
By Stoichiometry of the reaction:
67.2 L of hydrogen reacts with 22.4 L of nitrogen
So, 2 L of hydrogen will react with = of hydrogen.
As, the given amount if more than the required amount. Thus, hydrogen is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
67.2 L of hydrogen produces 44.8 L of ammonia.
Thus, 2 L of hydrogen will produce = of ammonia.
Thus, the volume of ammonia formed will be 1.33 L