Question

What will happen during the electrolysis of aqueous solution of CuSO4 in the presence of copper electrodes?

Answer 1

on the electro lysis of CuSO4 aq sol
CuSO4 will disassociate in Cu 2+ and SO4 2- ions
CuSO4->Cu 2+ +SO4 2-
impure copper is taken as anode(positive) and pure copper as cathode (negative) now this Cu 2+ will attracted towards the cathode
AT CATHODE
Cu 2+ + 2 electrons -> Cu
now this Cu will settle at cathode .
now the sol get deficient Cu 2+ ions now fron the positive end Cu get 2+ ions
AT ANODE
Cu + 2 protons -> Cu 2+
now Cu 2+ will move into the sol and again moves to cathode
after sometime anode end will get vanished

Answer 2

Answer:

Explanation:

(a, c) CuSO4 ⇋ Cu2+ + SO24-

      H2O ⇋ H+ + OH-

At cathode,

        Cu2+ + 2e- __> Cu2;      Eocell = 0.34 V

        H+ + e- __> H2;          Eocell = 0.00 V

(i) reaction will take place due to higher reduction potential.  

   At anode,

         2SO24- - 2e- __> SO28-;      Eocell = 1.96 V

         2H2O __> O2 + 4H+ 4e-;        Eocell = 1.23 V

The reaction with lower value of Eo will be preferred at anode, hence O2 is released at anode.