Question

What will happen if a parallel plate capacitor is filled with conducting slab?

Answer 1

$</p><p> </p><p> <div style="</p><p> padding:50px 5px;</p><p> text-align: center;</p><p> font-family:Monoscape;</p><p> background-image: linear-gradient(216deg, rgba(77, 77, 77,0.05) 0%, rgba(77, 77, 77,0.05) 25%,rgba(42, 42, 42,0.05) 25%, rgba(42, 42, 42,0.05) 38%,rgba(223, 223, 223,0.05) 38%, rgba(223, 223, 223,0.05) 75%,rgba(36, 36, 36,0.05) 75%, rgba(36, 36, 36,0.05) 100%),linear-gradient(44deg, rgba(128, 128, 128,0.05) 0%, rgba(128, 128, 128,0.05) 34%,rgba(212, 212, 212,0.05) 34%, rgba(212, 212, 212,0.05) 57%,rgba(25, 25, 25,0.05) 57%, rgba(25, 25, 25,0.05) 89%,rgba(135, 135, 135,0.05) 89%, rgba(135, 135, 135,0.05) 100%),linear-gradient(241deg, rgba(55, 55, 55,0.05) 0%, rgba(55, 55, 55,0.05) 14%,rgba(209, 209, 209,0.05) 14%, rgba(209, 209, 209,0.05) 60%,rgba(245, 245, 245,0.05) 60%, rgba(245, 245, 245,0.05) 69%,rgba(164, 164, 164,0.05) 69%, rgba(164, 164, 164,0.05) 100%),linear-gradient(249deg, rgba(248, 248, 248,0.05) 0%, rgba(248, 248, 248,0.05) 32%,rgba(148, 148, 148,0.05) 32%, rgba(148, 148, 148,0.05) 35%,rgba(202, 202, 202,0.05) 35%, rgba(202, 202, 202,0.05) 51%,rgba(181, 181, 181,0.05) 51%, rgba(181, 181, 181,0.05) 100%),linear-gradient(92deg, hsl(214,0%,11%),hsl(214,0%,11%));</p><p> "></p><p> </p><p> <span style="text-align: center; border-bottom:2px double #1cdb1e; color: #1cdb1e; ">Solution To Your Question &#x2193;</span> </p><p> </p><p> <p style="color: #fff;</p><p> text-shadow:0px 0px 10px rgb(215,240,204);</p><p> text-align: center;</p><p> font-weight: 500; "></p><p> </p><p> </p><p> If it is inserted in an existing isopotential plane, it has no effect. Otherwise the electric field is changed. Think of it as a change in the plate geometry. It will cease to be a capacitor and become a conductor.</p><p> </p><p> </p><p>=> This answer is verified by aliens too.</p><p></p><p> </p><p> &#128513; Hope You Liked It &#128513;</p><p> </p></p><p> </p><p> </p><p> <marquee style="color:#fff;"> <b>Mark Me as the brainliest and Follow Me &#128151;</p><p> </p><p> </b></marquee></p><p> </p><p> </p><p> </p><p> </div></p><p> </p><p> </p><p>$

Answer 2

If it is inserted in an existing isopotential plane, it has no effect. Otherwise the electric field is changed. Think of it as a change in the plate geometry. It will cease to be a capacitor and become a conductor.

‍‍♂‍♂‍‍‍♂‍♀‍♀‍♂‍♀‍♂‍♀️‍♂️‍♂⛹️‍♀‍♂‍♂‍♀‍‍‍‍‍‍‍‍