Question

what will happen if the distance between two particles is halved?​

Answer 1

Answer:

When the distance between two charged particles is halved, the force between them becomes four times.

Explanation:

$r_{2} = \frac{ r_{1} }{2} \: \\ \\ f_{2} = \: \\ \\ so \: f \propto \frac{1}{ {r}^{2} } \\ \\ \therefore \frac{ f_{2}}{ f_{1} } = ( \frac{ r_{1}}{ r_{2} } )^{2} = {( \frac{ r_{1} }{ \frac{ r_{1}}{2} } )}^{2} = 4 \\ \\ f_{2} = 4f_{1} = 4 \: times$

$\Large\textsf{Hope \: It \: Helped}$