what will happen to current passing through a resistance, if potential difference across it is double and the resistance is halved..
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According to Ohm’s law V=IR
Hence when nothing changed Io=VR
When potential difference is doubled and resistance is halved, then the current flowing is given by
I′=V′R′=2×VR2=4VR=4I0
Hence current will become 4 times the original value.
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