Question

what will ne the output ......
int y=5;
for (y<=19;y+=2)
System.out.println(y);​

Answer 1

OUTPUT :

5

7

9

11

13

15

17

19

$\underline{\mathbb{EXPLANATION}}$

↪ The initial value of y = 5 .

↪ The iteration value is y = y + 2 and hence y increases by 2 .

↪ The test condition is given y < = 19 .

↪ If the test condition is true , then only the loop is executed .

↪ If it is false , then it is terminated .

↪ In the above code , the value of y will begin from 5 and it will go n until the test condition is false .

↪ The test condition is false when y > 19 and hence the value of y will keep on increasing by 2 before it reaches more than 19 .

↪ The for-loop is given wrong in the question .

↪ The correct question will be :-

for (int y=5;y<=19;y+=2)  

System.out.println(y);​

↪ In the program y + = 2 means y = y + 2 .

↪ The + sign is the arithmetic operator used .

Answer 2

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