What will ratio of ages after ten years of two person if their present age ratio is 9:7?
Answers
Answered by
0
Heya...
Here is your answer ----
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Let the age of A be 7x
Let the age of B be 5x
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ATQ -----
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=> (7x + 10) : (5x + 10) = 9 : 7
=> (7x + 10) / (5x + 10) = 9 / 7
=> 7 (7x + 10) = 9 (5x + 10) [Cross multiplication)
=> 49x + 70 = 45x + 90
=> 49x - 45x = 90 - 70
=> 4x = 20
=> x = 20 / 4
=> x = 5
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• A's present age = 7x = (7×5) years = 35 years
• B's present age = 5x = (5×5) years = 25 years
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HOPE IT HELPS....!!!
Answered by
3
Answer:
Take ages as x...so a and be will be denoted as x...as we hve them in ratio7:5 so ...a=7x and b=5x..
now it is given after 10 years the ratio will be 9:7..so...eqution we will get will be
7x+10 9
_____ = __
5x +10 7
now cross multiply
7 (7x+10)=9 (5x+10)
49x+70=45x+90
49x-45x=90-70
4x=20
x=20÷4
×=5
so.....age of A= 7x
7×5
=35 years
age of B=5x
=5×5
=25 years
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