what will the be the minimum pressure required to compress 500 dm³ of air at 1 bar to 200dm³ at 30°c ?
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Answer:
P₁ = 1
P₂ = ?
V₁= 500 dm³
V₂= 200 dm³
Apply boyle's law p₁V₁=p₂V₂ to calculate p₂ as temperature remains constant.
p₂ = p₁V₁/ V₂ = 1 bar × 500 dm³/ 200 dm³ = 2.5 bar
2.5 is the required answer !
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