Chemistry, asked by Kavneet9962, 10 months ago

What will the density be if the radius of the sphere is halved?

Answers

Answered by Infinitum
0

initial density= m/4pi*(r)^3

Case I: If mass is kept constant (sphere is compressed)

In this case mass remains the same as earlier and only radius gets halved

density= mass/volume= m/4pi*(r/2)^3= m/4pi*r^3/8= 8(m/4pi*(r)^3)

= 8 times original density

Case II: If mass reduces (sphere is cut)

In this case density remains the same

#BAL #answerwithquality

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