Math, asked by Breadman, 2 months ago

What will the quotient and remainder be on division of ax 2 + bx + c by px3 + qx2 + rx+ 5, where p≠0

Answers

Answered by YashikaGitanshu
0

Answer:

Here, degree of px3 + qx2 + rx + s is greater than degree of the ax2 + bx + c Therefore, the quotient would be zero, And the remainder would be the dividend = ax2 + bx + c

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