What will you get as remainder and quotient on subtracting 46 from the number obtained by reversing the order of its digits and then dividing the result by 9 ?
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We know that 69 and 96 are having ten’s and unit’s place interchanged, i.e., they are having reverse digits.
So, sum of digits is 15.
We know that when ab + ba is divided by 11 then quotient is (a + b).
∴ The sum of 69 and 96 is divided by 11 then we get 15 (sum of digits) as our quotient.
(ii) 15
We know that 69 and 96 are having ten’s and unit’s place interchanged, i.e., they are having reverse digits.
So, sum of digits is 15.
We know that when ab + ba is divided by (a + b) then quotient is 11.
∴ The sum of 69 and 96 is divided by 15 (sum of digits) then we get 11 as our quotient.
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