What will you observe when hydrogen sulphide gas is passed through and aqua solution of Sulphur dioxide.
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a black precipate of copper will form
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2H2S+SO2(aq.) to give 3S+2H20
It forms yellow particles of sulphur are seen and sulphur dioxide is reduced to sulphur while hydrogen sulphide gas is oxidised to water vapour as redox reaction.
HOPE THIS HELPS☺️☺️
It forms yellow particles of sulphur are seen and sulphur dioxide is reduced to sulphur while hydrogen sulphide gas is oxidised to water vapour as redox reaction.
HOPE THIS HELPS☺️☺️
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