Question

What would be osmotic pressure of a solution
containing 5.85 g NaCl and 3.42 g sugar in 500
mL at 27°C?
(1) 103.4 atm
(2) 10.34 atm
(3) 1.034 atm
(4) 0.1034 atm​

Answer 1

• Osmotic pressure of a solution containing 5.85 g NaCl and 3.42 g cane sugar in 500 ml at 27 degree Celsius is 1.353 L-atm
• We know that osmotic pressure is given by π = CRT, where π is the osmotic pressure, C is the concentration, R is the universal gas constant and T is temperature.
• First we have to find the moles of solutes-
• Moles of NaCl = 5.85/58.5 = 0.1
• Moles of cane sugar = 3.42/342 = 0.01
• Total moles = 0.11
• Concentration = 0.11/500×1000 = 0.055
• By putting the values we get-

π = 0.055 × 0.082 × 300

π = 1.353 L-atm

Hence osmotic pressure is 1.353 L-atm

Regards

Answer 2

Explanation:

hope it helps....... ....

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