Physics, asked by jamal9151, 11 months ago

What would be the fictitious (pseudo) acceleration of the body lying on the equator of Earth in the radial direction away from the earth's centre due to its rotation?
(A) ωRe
(B) ω²Re
(C) ωRe ²
(D) ω²Re ² Where ω = angular speed of earth, Re = radius of earth

Answers

Answered by jitumahi89
0

Answer:

Option (B) is correct.

Explanation:

since whenever body is performing a rotational motion it experience a centripetal force which is

F_{c} =\frac{mv^{2} }{R}..................(1)

we know that

F=ma_{c}............................(2)

from (1) and (2)

ma_{c} =\frac{mv^{2} }{R}

so

a_{c} =\frac{v^{2} }{R}.....................(3)

we know the relation between linear and angular speed

v=Rω................................(4)

from (3) and (4) we get,

a_{c} ={R\varpi^{2} }

So the rquired option is (B).

Answered by ghoraikaushik1
1

Answer:

(B) R_{e} w^{2}

Explanation:

Centripetal acceleration a_{c} = \frac{V^{2}}{R_{e}}

but V = R_{e}ω

a_{c} = \frac{R_{e}^{2}w}{R_{e}} = R_{e} w^{2}

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