Question

'What would be the final temperature of a mixture of 50 g of water at 20degrees celsius temperature & 50 g of water at 40 degrees celsius temperature?

Answer 1

Given Mass (M₁) = 50g
Temperature (T₁) = 40°C 
Mass (M₂) = 50g
Temperature (T₂) = 20°C
By the method of mixture , Final temperature (T) = (M₁T₁+M₂T₂)/M₁+M₂
                                                                       = (50×40+50×20)/50+50
                                                                       = 3000/100
                                                                       = 30° C

Answer 2

Answer:

30°C

Explanation :

Given,

Mass m1 = 50g

Temperature T1 = 40°C

Mass m2 = 50g

Temperature T2 = 20°C

By using method of mixtures,

Final temperature

T = m1T1 + m2T2/m1 +m2

= 50×40+50×20/50+50

= 2000+1000/100

= 30°C

The final temperature = 30°C